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How can I itterate through a 2d array in C given as a pointer?

So I have a function like this: int *func(int *arr, size_t n); Where *arr is the 2d array and n is the size of the array. The array is a square, so n is both width and height. I tried doing this: int val = arr[x][y]; But it gave me an error saying the subscripted value is neither array nor vector. Does someone know what I can do?

3rd Jul 2022, 5:38 PM
ChrisVIN
ChrisVIN - avatar
2 Réponses
+ 2
You can do it in multiple different ways. One would be to cast the array first: int** nArr = (int**)arr; Int val = nArr[x][y]; An array, even a 2d array ist consecutive in memory, so you can also: int val = *(nArr+(n*x)+y);
3rd Jul 2022, 5:53 PM
Erarnitox
Erarnitox - avatar
+ 1
You can use a loop like for(int i=0; i<n; i++){ for(int j=0; j<n; j++) printf("%d ", *(*(arr+i) + j) ); printf("\n"); } edit: ChrisVIN
3rd Jul 2022, 5:53 PM
Jayakrishna 🇮🇳