Why error at coming at line temp= total%10; err msg: invalid Binary operands to binary expression

Question

vector<int> sum(vector<int> A, int k){
int n= A.size();
double sum= 0;
for(int i=0;i<n;i++){
sum= (sum+A[i])*10;
}
sum/=10;
int temp_int = (int)sum;
double total= temp_int+k;
double temp;
vector<int> s;
while(total>0){
temp= total%10;
total/=10;
s.push_back(temp);
}
reverse(s.begin(),s.end());
return s;
}

Answer 1

Because you can only do modulus operations with integers.

Answer 2

SHŪBHÃM, adding to Marcos Chamosa Rodríguez's good answer, there is a library function that can do modulo with floating point, if that is your intention. See details for calling fmod() here:
https://cplusplus.com/reference/cmath/fmod/

And since you are using both, quotient and remainder, maybe div() or modf() would be more useful:
https://cplusplus.com/reference/cstdlib/div/?kw=Div
https://cplusplus.com/reference/cmath/modf/

Answer 3

SHŪBHÃM long long can easily store 9999999999 and 1 more. If your program shows a wrong answer, then check for anyplace in the data path where it might be causing overflow in a smaller data type (i.e., getting copied into an int).

Answer 4

Brian I have used long long int and I'm not getting any error but for addition of long numbers like 9999999999+1 it's giving incorrect ans

Answer 5

Brian thanks for solution