Trying to write a function that returns the average of it's two arguments. What's wrong with my code?

Question

This is my first steps in JS, but I have some skills in Python, so it's helping me a lot right now.
However, my code doesn't work, while all syntax seems to be fine. I'm not asking to write the code for me, just point me, please, on my mistakes.
Thank you in advance!

function avg(num1, num2, num3) {
num1=56
num2=43
num3=(num1+num2)/2
console.log(num3);

Answer 1

first of all u haven't used semicolons use them at the end of declaration of a variable

Answer 2

and you should have actually used return function

Answer 3

here is the solution

https://code.sololearn.com/WbK3V2rWIviS/?ref=app

Answer 4

won't work,you have to specify the calculations to be carried out in the return keyword

Answer 5

function avg(num1, num2) {
console.log(num1+num2)/2
}

avg(56,43) // @DIY Mods, you have to put this in order to run the function

----

Better way using arguments as input parameter so no constrain to 2 numbers

function avg() {
nums = Array.from(arguments)
console.log(nums.reduce((acc,a)=>acc+=a)/nums.length)
}

avg(56,43)
avg(56,43,1)

// * @_Retr0/-, please note that Javascript statements ended with semicolon (;) is not required now.

Answer 6

I can not use html or css at all. Only JS.
How about this:
function avg(num1, num2, avg){
num1=34;
num2=54;
avg=(num1+num2)/2;
return avg;

Answer 7

Ok, it works this way:

var x = myFunction(65, -9);

function myFunction(a, b) {
x = (a+b)/2;
console.log(x)
}

But how can I get an output with return, without var x = myFunction(65, -9); ?
I can assign the values to 'a'&'b' to make it like this:

function myFunction(a, b) {
a = 44
b = 67
x = (a+b)/2;
console.log(x)
}

But it doesn't work