Please explain the output.

Question

#include <iostream>
using namespace std;

int main() {
int x=2;
switch (x){
case 1:{x*=x;}
case 2:{x*=x;}
case 4:{x*=x;}
default :{x*=2;}
}
cout<<x;
return 0;
}

Answer 1

#include <iostream>
using namespace std;

int main() {
int x=2;: //x=2
switch (x){//True all cases will be excuted
case 1:{x*=x;} //2*2=4
case 2:{x*=x;} //4*2=8
case 4:{x*=x;} //8*2=16
default :{x*=2;} //16*2=32
}
cout<<x; //32
return 0;
}

Answer 2

default is executed only when all the given cases tends to be false, isn't it ?

Answer 3

Your break statements are missing. So all cases after a matching case will run (fall through). If there was no match then just the default would run.
x is 2
case 2, case 4, and default are all ran
case 2:
x*=x 2 * 2 = 4 x is now 4
case 4:
x*=x 4 * 4 = 16 x is now 16
default:
x*=2 16 * 2 = 32 x is now 32

32 is output

Answer 4

@chaoticdawg the question which I got didn't contain any break statement. this question was asked in a challenge round and didn't contain break statement

Answer 5

Ah, well then the answer is 32 due to the reasons I stated above.

Answer 6

yes now u can say the answer is 32. since there is no break statement, the code goes on working until it finds a final stop. I got it !!! thanks to both 😊😊

Answer 7

@ Elie
case 1 is not ran x is 2