Problem with array in Java.

Question

Hi, I have small problem with this code, in a second array it returns me place in memory instead of result ( I mean it should return 1 and 2 like in alphabet method a and b).

Answer 1

public class Chair {
public static void main(String[] args) {
Chair chair = new Chair();
System.out.println(chair);
Tree tree = new Tree();
System.out.println(tree);
System.out.println(new Tree());
//System.out.println(Tree.numbers());
// This won't work numbers() returns an array
}

public static char[] alphabet() { // this needs to be a char array not a String array
return new char[] {'a', 'b'};
}

@Override
public String toString() {
return String.valueOf(alphabet());
}

static class Tree {
static int[] numbers() {
return new int[] {1,2};
}

@Override
public String toString() {
String s = "";
for(int i: numbers()) {
s += String.valueOf(i); // int arrays don't work the same way as a char array will with valueOf. instead you need to loop over each int within the array.
}
return s;
}
}
}

Review the overloaded versions of the method and what the different possible parameters can be.
https://www.javatpoint.com/java-string-valueof

Answer 2

Public class Chair{
Public static void main(String[]args){
Chair chair = new Chair();
System.out.println(chair);
Tree tree = new Tree();
System.out.println(tree);
System.out.println(new Tree());
System.out.println(Tree.numbers());
}
public static String[] alphabet(){
return new String[] {"a", "b"};
}
@Override
public string toString(){
return String.valueOf( alphabet())};
static class Tree{
static int[] numbers(){
return new int[] {1,2};
}
@Override
public string toString(){
return String.valueOf( numbers())
}
}
}
Why it does not works in case in array numbers?