Can someone pls explain the output of this snippet

Question

int x=0; for (int z=0; z<5; z++) { if((z>3) && (++x>2)) { x+=7 } } System.out.print(x);

Answer 1

when your if statment is checked z = 4 , it then increments x by 1 as it checks conditions as its still false no further increments are made and the loop ends.

z<=6 will allow the if statement to return true and incremenet x by 7

Answer 2

int a = 0;
boolean q = false && ++a>-5;
System.out.println(a);

this prints 0 and if you put '||' it prints 1

I think statement after false && doesn't get executed so x doesn't increase while z<3 then x becomes 1 then loop finishes but I am not sure

Answer 3

Somebody else had this question and we were all very confused.

The output appears to be 11, but somehow it isn't.

Is it a challenge question?

Answer 4

Here && operator works as follows : a&&b
If a is false then the compiler does not evaluate the value of b as we know that the output is going to be false. So over here x is never incremented except when z=4 but the value of x at z=4 is 1 but in the x must be greater than 2 to enter the if block . Therefore According to me it should be 1 as it was incremented once in the block