Not operator in c

Question

https://code.sololearn.com/c2QVVBBEXtCf/#c

I am having a great confusion in not operator..
Can anyone explain me clearly about it that how it evaluates in the above program.

Answer 1

First you have to understand what % is doing.

It finds the modulo(reminder of a division) of a number.

In C any non-zero value is considered true.

So, if(!(2%2)) is true so the loop continues
same for
if(!4%2) is true and the loop continues without increasing the value of count.

4%2 = 0
2%2 = 0 which in boolean logic false
but the condition is
if(not (0))
continue;

so it continues.

if(not (nonzero)) is false-
this line may not make sense at first so stick with the earlier explanation.

Answer 2

Akib Reza

After your explanation..
I understanded it as
if(!(0%2))
In case of modulo it takes the remainder value so 0%2 is 0
so if(!0) means the value is not zero , so it is a nonzero value like 1 or -1..
Nonzero value means it is true so the loop continues..
The above condition is applicable 0,2,4 and 6
In case of 1,3,5...how I need to consider???
if(!(1%2))
so the remainder as 1
if(!1) whether it becomes 0 or anyother value ??

Answer 3

Its just boolean.
if(!1) is false hence the count++;

You should study basic boolean algebra and logic gates. It will clear things up more.

if just checks whether the condition is true or false. If its true it continues else doesn't.
if(0) is false so nothing works inside condition
if(!nonzero) is also false and doesn't do anything