Need help to write a program that prints all numbers between 1,000 and 10,000 that are divisible by 6 but not 12.

Answer 1

basic way is to use condition (a%6==0&&a%12!=0) & run through all integers in range, though Bennett Post idea is more efficient as it removes the need to check condition for every integer in range & reduce the number of iterations in loop.

Answer 2

that is happening because 12 is div. by 6, else we need to iterate through whole range & check for each integer.
//time saved

Answer 3

Bennett Post so the loop will work like
6 18 30 42...........n+12
Really effective.

Answer 4

https://code.sololearn.com/cE1LdLehSw7V/?ref=app
I tried to implement both ways into a dynamic programming.

Answer 5

https://code.sololearn.com/cV9mfiM6V0QX/?ref=app

Answer 6

😂 😂 😂, I feel embarrassed
Thanks for the correction Bennett Post
Just wrote it, didn't even check it

Answer 7

you can use numpy to solve this problem

import numpy as np
arr=np.array(range(1000,10000))
arr2=arr[arr%6==0]
print(arr2)

Answer 8

Or you can use this ;

a=range(1000,10000)
res=list[filter(lambda x: x%6==0,a)]
print(res)

Answer 9

https://code.sololearn.com/cWsepb21LdG7/?ref=app

This also should reduce the time spent