Python Set Symmetric Difference

Question

A = {1, 2, 3, 4, 5}
B = {1,4, 5, 6, 7, 8}
C = {3,1}
print(A^B^C)

OUTPUT:
{1, 2, 6, 7, 8}

Why 1 is there? It is common so it should be eliminated.

Answer 1

It's the same as print(A^(B^C)) (or maybe (A^B)^C if it's left associated, I don't know)

Try this and it'll make sense:

D = B^C
print(D)
print(A^D)

Answer 2

harshit
For the first
{1, 2, 3, 4, 5} ^ {1,4, 5, 6, 7, 8}
== {2, 3, 6, 7, 8} (without 1)

then
{2, 3, 6, 7, 8} ^ {3,1}
= {1, 2, 6, 7, 8}

So 1 in game again