How to print 1 1 2 4 7 13 24 44

Answer 1

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner input= new Scanner(System.in);
System.out.println("Enter the number of terms in the series");
byte j= input.nextByte();
long[] s= new long[j];
s[0] = s[1]=1;
s[2] = 2;
System.out.print ("The first "+j+ " terms of the series are \n" +s[0]+", "+s[1]+", "+s[2]);
for(int i=3;i<j;i++)
{
s[i]=s[i-2]+s[i-1]+s[i-3];
System .out.print(", "+s[i]);
}
}
}

For the series to stop at 44, give the input as 8 as the number of terms in your series is 8

Answer 2

Done with recursion. In fact, this is similar to Fibonacci numbers.

public static int fab3(int n) {
if (n < 0) return 0;
if (n < 2) return 1;
return fab3(n-1)+fab3(n-2)+fab3(n-3);
}

public static void main(String[] args) {
for (int i=0; i<8; i++)
System.out.print(fab3(i)+" ");
}

Answer 3

int a=1;
int b=1;
int c=2;

for(int i=0; i<3; i++){
System.out.print(a + " ");
System.out.print(b + " ");
if(c<44){
System.out.print(c + " ");
}
a=c+b+a;
b=a+c+b;
c=b+a+c;
}