Please solve this code problem

Question

arr = list(input("enter your 4 digits binary code"))
a=int(arr[0])
b=int(arr[1])
c=int(arr[2])
d=int(arr[3])

for i in range(len(arr)):
if (int(arr[i])==0 or int(arr[i])==1):
if (a,b,c,d==0,0,0,0):
print("0")
elif(a,b,c,d==0,0,0,1):
print("1")
elif(a,b,c,d==0,0,1,0):
print("2")
elif(a,b,c,d==0,0,1,1):
print("3")
elif(a,b,c,d==0,1,0,0):
print("4")
elif(a,b,c,d==0,1,0,1):
print("5")
elif(a,b,c,d==0,1,1,0):
print("6")
elif(a,b,c,d==0,1,1,1):
print("7")
elif(a,b,c,d==1,0,0,0):
print("8")
elif(a,b,c,d==1,0,0,1):
print("9")
else:
print("hi")

break

else:
print("enter binary code")
break

Answer 1

For me the most simple way would be to keep input as string. Then convert it to int, with a second argument for the base system.

inp = input('enter binary code: ')
if all(i.isdigit() for i in inp):
print(int(inp, 2))
else:
print('wrong input')

Answer 2

Compare variables via tuples, therefor put them in parentheses:

if ((a,b,c,d)==(0,0,0,0)):
print("0")

Btw. your loop is checking if any of the characters entered is 0 or 1. So if e.g. the you enter 1,5,0,0 it would still print "hi".