Why output is 'Try Again' ?

Question

int main()
{
#if !SOLO
printf("Try Again");
#else
printf("Sololearn");
#endif
return 0;
return 0;
}

Somehow string '!SOLO' is getting converted to a non-zero value. Can someone explain how ?

Answer 1

Is this all the code? Is SOLO defined? If not then SOLO is 0 and it is saying !0 which is 1.
#define SOLO 1

Answer 2

Ya, that's pretty much what I said. Lol
Add the #define line from my previous post before main (or at least before the #if) and it will work as expected.

Answer 3

ChaoticDawg This is the whole code and it runs without any error. My guess is if SOLO is not defined (as in this case) it will be treated as 0.