whats wrong?

Question

my goal is to prevent the user from writing an Integer, i want the input to be a String.
how can i make it work?
i used a method called "hasNextInt" that i found online and it doesnt do the work, or i just messed up somewhere...

https://code.sololearn.com/cb83Fx9EvB2k

Answer 1

yahel hasNextInt() and hasNextLine() are a method of Scanner class. You can't apply on String. So here x.hasNextInt() and x.hasNextLine() are Wrong. Here should be scan.hasNextInt() and scan.hasNextLine()

Answer 2

yahel Yes you will have to use 2 scanner, 1st for input and 2nd for to do operation on that input value. So you can do like this.

Scanner scan = new Scanner (System.in);

String name = scan.nextLine();

Scanner sc = new Scanner(name);

if (sc.hasNextInt()) {
System.out.println("error - write a String, not an integer");
}

but here if statement will work on only input like 123456. It will not work on dgdgg233 because hasNextInt check on each iteration so here while loop will work.

Answer 3

AJ Anant , i did that and now i have 2 Scanners. meaning that the program forces me to write 2 inputs... how can i fix that?
code:

import java.util.Scanner;
public class Main
{
public static void main(String[] args) {

System.out.println("Whats your name ?");

Scanner scan = new Scanner (System.in);
String x = scan.nextLine();
x = x.substring (0 , 1).toUpperCase() + x.substring (1);

if (scan.hasNextInt()){

System.out.println("error - write a String, not an integer");

}else if (scan.hasNextLine() && x.equals ("Yahel") || x.equals ("John")){

System.out.println("You are welcome , " + x);

}else if (scan.hasNextLine() && x != ("Yahel") || x != ("John")){

System.out.println("Go away , " + x);

}else{

System.out.println("Error");

}

}
}

Answer 4

so is there a simpler way to prevent user from writing numbers?