How to take square root of numbers in python?

Question

Please Suggest any way to take square root of numbers in python?

Answer 1

>>> print(2**.5)
1.4142135623730951

Everything seems to be working...

Answer 2

x = float(math.sqrt(s(s-a)(s-b)(s-c)))
cant this work?

Answer 3

its just showing -
Typerror: 'float' object is not callable

Answer 4

This is the code https://code.sololearn.com/c8LNEd3OHeRA/?ref=app

Answer 5

can u gibe me an example

Answer 6

Thank you very Much😊😊😊😇

Answer 7

Well I am
Have you cleared it? If yes , can you give
some tips...

Answer 8

Oh yes!
SoloLearn is my practice book..
Byw what was your rank?

Answer 9

👍👍👍 When did you give it?

Answer 10

Sounds Cool😎😎😎

Answer 11

@Kuba_Siekierzynski But it's still not working(x**0.5)

Answer 12

I actually forgot to mention the brackets. It's working.Thank you🙂☺☺

Answer 13

x**0.5 gives a square root of x and does not require importing the math module.

Answer 14

math.sqrt (n)

Answer 15

it should work.
post your code link if facing problem.
it is triangle ▲ value na?

Answer 16

use multiplication sign

Answer 17

it is working. ..write s*(s-a)* ...like this

Answer 18

check this
https://code.sololearn.com/cNVXiDGpd2Qm/?ref=app

Answer 19

its ok.
btw are you preparing for JEE?
this formula remind me of my preparation days.

Answer 20

hey! in exam hall...you won't get compiler so practice to do manually.
and if you are in preparation this year..I suggest you to concentrate on that only