why output is repetitive 1

Question

#include<iostream>
#include<conio.h>

using namespace std;

int main()
{
long int a, i ,s=0;
for(i=11;i<=99;i++)
{

cout<<i<<":";
a=i%10;
s=s*10+a;
i=i/10;

}

getch();
return 0;
}

Answer 1

in loop first i =11, you printing it. But after
I = i /10 => now i=1, then i++ cause I =2. It prints again.. Next by i=i/10 make i =0... Next i++ cause i =1 it prints..
Next I =i /10 => I =0, I ++ this will repeating infinitly.. Because i<=99 always true...
So output is what you seen...

Answer 2

Jayakrishna🇮🇳 i appreciate your response but i didnt understand how i++ would be executed for i=1 as you said when it is not in the domain of loop(i=11;i=99;)

Answer 3

Jayakrishna🇮🇳 aha i got it after contemplating 😀😸