0
n order of a radical for folat power
For radical 8 by order 3 we can write 8^(1/3) But When the compiler executes code (1/3) says we a float number and insted 2 take we a number near to 2 Becuse this is work with 8^0.3333333333 no radical 8 by order 3 8^0.3333333333 = 1.9999999999 Radical 8 by order 3 = 2 How we can fix this bug?
2 odpowiedzi
+ 1
but this is give we 0 and 8^0=1
0
Vadivelan this is not my problem