Why does that the test case 1 is failing???

Question

import math
n = input().split(" ")
a = 0
for i in n:
if i not in "@#&+()/?":
for x in i:
b = len(x)
a = a+b
x = len(n)
print(math.ceil(a/x))

You are in a college level English class, your professor wants you to write an essay, but you need to find out the average length of all the words you use. It is up to you to figure out how long each word is and to average it out.

Task:
Takes in a string, figure out the average length of all the words and return a number representing the average length. Remove all punctuation. Round up to the nearest whole number.

Input Format:
A string containing multiple words.

Output Format:
A number representing the average length of each word, rounded up to the nearest whole number.

Sample Input:
this phrase has multiple words

Sample Output:
6

Answer 1

import math
n = input().split(" ")
a = 0
c = ""
for i in n:
for j in i:
if j not in "@#&+()/?":
c+=j
#b = len(x)
a +=1
x = len(n)
print(math.ceil(a/x))

Answer 2

https://code.sololearn.com/cg7v4LCRF7Gs/?ref=app

Answer 3

In the given code only few punctuation mentioned i.e. --> "@#&+()/?"

But there are many more like ---> ~" ' - _ ] [ { .....etc.
TIP : rather the excluding the counting of punctuation count the alphabet :)

Answer 4

import math
import re

w = re.sub(r"\W", " ", input()).split()
a = sum(map(len, w))/len(w)
print(math.ceil(a))

# split default separator is space
# regex \W match not word chars (ascii alphanumerics + underline)
# re.sub replace pattern with substitute string in input string
# sum return sum of iterable
# map return iterable mapped with function