+ 2

Hi, please help me with operator overloading in C++. Thank you=)

In my below code, I have mentioned a comment line inside main function. My doubt is, why is both working? Is the compiler doing any implicit conversion there (like in the case of pass by reference(not by address))? I know operator overloading, just have to understand how it works. Have a nice day=) https://code.sololearn.com/cABCNIwPqi03/?ref=app

7th Jul 2021, 9:08 AM
Rishi
Rishi - avatar
3 odpowiedzi
+ 1
When C++ reads A + B It sees it as add(A, B) It now searches if there is a definition of 'operator+' that has parameters of those types And uses that to perform the command So they both work becouse they say the same thing
7th Jul 2021, 12:29 PM
Angelo
Angelo - avatar
+ 1
Angelo wow, I just got the answer I guess. Just one more thing. Is there another format for the same function? Like, "MyClass res=operator+(&obj1,obj2)" which also does the same job?
8th Jul 2021, 1:41 AM
Rishi
Rishi - avatar
+ 1
Kind of... While C++ uses samething similar to MyClass::operator+(&obj1, obj2) to perform the job, That function doesn't exist for you But, if you follow the common way to declare operators, than operator+ would be friend and not a member function, so there would actually be MyClass::operator+
8th Jul 2021, 9:56 AM
Angelo
Angelo - avatar