What is happening with this operator

Question

print(1|0)

Answer 1

The pipe (I think?) sign is a bitwise OR binary operator. It tests if the bits in the binary equivalents of the numbers contain at least a 1. In simple terms:

1 = 0001
0 = 0000
--------------
0001

Thus, 1 | 0 is 0001 which is outputted as 1 in decimal.

From the above, the numbers are first converted into their binary forms. 1 is 0001 while 0 is 0000. Then an operation is carried out on each column. A single digit in their binary form is a bit. If 1 is found at least once in the column of bits, 1 is returned as an output. The only case 0 is returned is if both bits are 0.

Below is the truth table for OR (|) operator:

1 0 = 1
1 1 = 1
0 1 = 1
0 0 = 0

Let's see 5 | 2.
5 = 0101
2 = 0010
-------------
0111
Therefore, 5 | 2 = 0101 | 0010 = 0111 = 7.

For more information on bitwise operators, ask Google. ^_^

Answer 2

For integer types (which is your example), it's the bitwise or operator. You can apply | also to sets, which gives the union of these two sets.

Answer 3

哈？