creating a string from the items of secondary if main string met the condition

Question

Hi,

I work on a code and i have difficulties on a part of it.

There is main string:
'(a bc defg.)'

The secondary string:
'iamhere'

I want to create a new string by comparing these two strings and get:
'(i am here.)'

condition: if item in main string is not a letter, then add item to new string. Else add item of secondary string into the new string

i could not do it for loop using isalpha function. Anybody have an idea how can i achieve the desired string?

Answer 1

mst="abcde."
sst="hello"

newst=sst + "".join(i for i in mst if not i.isalpha())

print(newst)

Answer 2

(i am here.) make sense

o='(a bc defg.)'
s='iamhere'
s =list(s)

for i in range(len(o)):
if not o[i].isalpha():
s.insert(i,o[i])
print(''.join(l for l in s))

Answer 3

Hercule Poirot
you can’t get (hello.) by comparing this strings there is no “l” and “o” letters

Answer 4

@ simba
if item in main string is not a letter, then add item to new string. Else add item of secondary string into the new string

Answer 5

ubai
not exactly. actually there are parenthesis too. i edited my sample strings to make my question clearer.

Answer 6

ubai ty a lot it worked 😀