The printed result of this binary number(x1,x2) is not what I want.(if I input :1234)Can anyone help me?

Question

#include <stdio.h>
int Count_one(int binary_number){
if(binary_number == 0) return 0;
return Count_one(binary_number / 10) + binary_number % 10;
}

long long int HexadecimaltoDecimal(long long int hexadecimal_number, int power){
if(hexadecimal_number == 0) return 0;
return HexadecimaltoDecimal(hexadecimal_number / 10, power * 16) + hexadecimal_number % 10 * power;
}

long long int DecimaltoBinary(long long int n, int power){
if(n == 0) return 0;
return DecimaltoBinary(n / 2, power * 10) + n % 2 * power;
}
int main(){
int time, num, b1, b2;
long long int X1, X2;

scanf("%d", &time);
for(int i = 0;i < time;i++){
scanf("%d",&num);

X1 = DecimaltoBinary(num, 1);
b1 = Count_one(X1);

printf("X1=%lld\n",X1);//I added it myself
X2 = DecimaltoBinary(HexadecimaltoDecimal(num, 1), 1);
b2 = Count_one(X2);
printf("X2=%lld\n", X1);//I added

printf("%d %d\n", b1, b2);
}
return 0;
}

Answer 1

I would like to help you, could you be more specific? give an example of input and expected output
And what is the problem itself, is that it prints "time" times?

You could also attach the code directly from the playground next time

Answer 2

UVA topic is Funny Encryption Method

Answer 3

When I input 1234
output:
X1 = 1421075418//not a binary number
X2 = 1421075418//not a binary number
33 27

Answer 4

Example input:
3
265
111
1234
Expect output:
3 5
6 3
5 5