What's wrong with my def code?

Question

I need to calculate the area of a rectangle.
What's wrong with my code?

length = int(input())
width = int(input())
def area (length, width):
print(length*width)

if length == width:
print('Square')

Answer 1

What is it supposed to do exactly?
You have never called your function...

Answer 2

You can do it like this:
1. Define a function
2. Get the the input
3. Call the function

def area(a, b):
if a == b:
print("Square")
print(a*b)

length = int(input())
width = int(input())

area(length, width)

Answer 3

def area(a, b):
print(a * b)
if a == b:
print("Square")

Answer 4

Call the function before printing 'Square'

Answer 5

Supposed to multiply length by width. And print 'Square' if they are identical

Answer 6

How do I make a code that will show the result first, and then Square?
I tried moving it around, and it showed errors

Answer 7

ariPT call area function before "if length == width:"

Answer 8

Or simply remove function declaration and leave print instruction

Answer 9

Thank you all.
I'm very much a beginner, and am still having trouble, despite your suggestions.
Could one of you please write a full code? I'm trying to see what I missed

Answer 10

def area(a, b):
print(a*b)
if a == b:
print("Square")

length = int(input())
width = int(input())

area(length, width)

Answer 11

Thank you!
Why do I need to define area both as a,b and as length,width?

Answer 12

You can call them what you want. This version should only show you, that the variables inside a function are others then the variables outside the function.

Answer 13

Thank you very much, I appreciate your help