any smaller alternative for this??

Question

tips and tricks to achieve this but with lesser code
https://code.sololearn.com/ci90j4YhcP1B/?ref=app

Answer 1

https://code.sololearn.com/cGp4RPQtOXxM/?ref=app

Answer 2

xSOGIx

first check if character exist in dictionary. if exist then increment count otherwise put count 1

https://code.sololearn.com/cebXGf11Gq58/?ref=app

Answer 3

A͢J Slick thanks for helping out <3