How to display all perfect numbers between 1 to 1000 along with their factors?

Answer 1

Perfect number is a positive integer that is equal to the sum of its proper divisors, excluding the number itself.
For example: 6 is a perfect number since divisor of 6 are 1,2,3 and the sum of 1,2,3 equal 6.

#include <iostream>

void perfect(int);
int main()
{
int number;
for (number=1; number <= 1000 ; number++)
perfect(number);
return 0;
}
void perfect(int number)
{
int total = 0;
for (int i = 1; i < number; i++)
{
if (number % i == 0)
total += i;
}
if (number == total)
{
for (int x = 1; x < number; x++)
{
if (number % x == 0)
std::cout << x << " + ";
}
std::cout << " = " << number << std::endl;
}
}

It will print:
1+2+3 = 6
1+2+4+14 = 28
1+2+4+8+16+31+62+124+248= 496

Answer 2

Thanks a lot :)