function abc(a){ return(function(y){ return y+1; }) (++a)+a; } alert(abc(2));

Question

//output= 7
//do u have any explanation?

Answer 1

You put an argument a as 2. a gets pre-incremented by one and so now equals 3. You add up 3+3 and get 6. But you asked the function to return the result plus one (return y+1) and so you receive 7 in the end.

Answer 2

Try formatting the code in the description