+ 1
If and else confusement
im build a script with python in linux.the python version:2.7 here the example script tanyatb = (str(raw_input("do u know how many that? Y/N "))) if (tanyatb==("y")or("Y")): print("its working") else: print("its not working") idk know why raw_input is defined in here, but when i input that 'y' its print 'its working'.but when i input 'n' its print ' its working' too.im tried if (tanyatb!=("y")or("Y")): and if not(tanyatb==("y")or("Y")): then im input 'n' , 'its working'.how to print 'not working'?
4 odpowiedzi
+ 1
There are a a few errors here
you don't need to convert raw_input to a string
tanyatb = raw_input("do u know how many that? Y/N ")
will work fine
You also don't need brackets in your if statement
if tanyatb.lower() == "y":
print("it's working")
else:
print("it's not working")
+ 1
working well.u just help my big project,thnx
0
raw_input is not defined in learn python
0
yeah,solo learn code playground sucks.i will try that.thnx