Write a prog in c/c++

Question

to assign 4 different values, each 4 times repeated, to 16 different variables, randomly...

ex:
a=3. e=2
b=4. f=1
c=2. g=3
d=2. h=1
A=1. E=4
B=4. F=4
C=3. G=1
d=2. H=3

where 1,2,3 and 4... each repeated exactly 4 times

Answer 1

rand() and srand() both are standard functions present in cstdlib header file.

Answer 2

will we use 4 loops?

Answer 3

instead of taking 16 variables you can use array of size 16 and assign values to it using a for loop.

Answer 4

well!! using array is ok..

Answer 5

can anyone give me a prog pls!!

Answer 6

#include <iostream>
using namespace std;

int main() {
int a[16];
for(int i=0;i<16;i++){
cin>>a[i];
}
for(int i=0;i<16;i++){
cout<<a[i]<<" ";
}
return 0;
}

Here, you can assign whichever value like.
consider a[0] as first variable,a[1] as second and so on.

Answer 7

sorry but the values are to be assigned randomly and by the compiler

Answer 8

Sorry I didn't see "randomly" word in your question.😂
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int main() {
srand(time(0));
int a[16];
for(int i=0;i<16;i++){
a[i] = rand()%4 + 1;
}
for(int i=0;i<16;i++){
cout<<"a["<<i<<"] = "<<a[i]<<endl;
}
return 0;
}

Answer 9

what does that cstdlib do there

Answer 10

I dont think this will print each value exactly 4 times

Answer 11

aren't they included in iostream

Answer 12

then you can do it like this:
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int main() {
srand(time(0));
int a[4],b[4],c[4],d[4];
for(int i=0;i<4;i++){
a[i] = rand()%4 + 1;
b[i] = rand()%4 + 1;
c[i] = rand()%4 + 1;
d[i] = rand()%4 + 1;
}
for(int i=0;i<4;i++){
cout<<"a["<<i<<"] = "<<a[i]<<endl;
cout<<"b["<<i<<"] = "<<b[i]<<endl;
cout<<"c["<<i<<"] = "<<c[i]<<endl;
cout<<"d["<<i<<"] = "<<d[i]<<endl;
}
return 0;
}

Answer 13

no they are not included in iostream.