Quiz

Question

question:how to open a website?
like:
input:www.yahoo.com
output:a website page”www.yahoo.com”
Any language except JavaScript,HTML,CSS
is welcome.

Answer 1

This can be done in Python using the "webbrowser" module:

" # Tutorial: https://www.idiotinside.com/2015/03/07/open-an-url-on-web-browser-programmatically-in-python
# Documentation: https://docs.python.org/3/library/webbrowser.html
# Tested on Python 2.7.6

import webbrowser

url = 'http://idiotinside.com'

# Open URL in new browser window
webbrowser.open_new(url) # opens in default browser

# Opens in safari browser
webbrowser.get('safari').open_new(url)

# Open URL in a new tab
webbrowser.open_new_tab(url) # opens in default browser

# Opens in safari browser
webbrowser.get('safari').open_new_tab(url) "

Source: https://www.idiotinside.com/2015/03/07/open-an-url-on-web-browser-programmatically-in-python/

" How to open a webpage using java code"

http://www.instanceofjava.com/2016/08/how-to-open-webpage-using-java-code.html?m=1

Answer 2

in python using urlib and regex

import regex as re
import urllib.parse
import urllib.request

try:
url = 'https://google.com/search?q=test'
headers = {}
headers['User-Agent'] = 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:41.0) Gecko/20100101 Firefox/41.0'
url = 'https://pythonprogramming.net'
value = {'s':'basic', 'submit' :'search'}
data=urllib.parse.urlencode(value)

data = data.encode('utf-8')
req = urllib.request.Request(url,data,headers=headers )
resp= urllib.request.urlopen(req)
respData=resp.read()
print(respData)

save = re.findall(r'<p>(.*?)</p>',str(respData))
for i in save:
print(i)
save = open('headergog.txt','w')
save.write(str(respData))
save.close()

except Exception as e:
print(str(e))

Answer 3

@Sreejith Thank you! Is this right?

import webbrowser
webbrowser.open(‘www.yahoo.com’)

Answer 4

yes it's right

this may help you
https://docs.python.org/2/library/webbrowser.html