How to measure the execution time of this code snippet?

Question

def sumOfN(n):
return (n*(n+1))/2

Answer 1

you can mesure the time execution with using in first line: "start=time.time()"
and the final line: "print(time.time()-start)" and it will give you the time ,

Answer 2

there's no way to "measure" code execution in milliseconds per se, but if you used big O notation, this code has a time of O(1)