Can anyone explain this program

Question

char * a="Coding";
char *b=(++a)+1+1;
printf("%c",*b);

Ans = i
please anyone explain here.
Thanks in advance.

Answer 1

adding 1 to pointer results in change of memory address by sizeof(base class or data type)
so ++a on char *a causes char *a to point to next memory address i.e. address of letter o.
Now doing that again two time as +1 causes to move pointer to d and then to i.
so i is printed

Answer 2

thanks a lot sir.