Can some one explain this code to me please. I'm lost on why the answer is 13.

Question

int x =3;
while(x++<10){
x+=2;
}
cout << x;

Answer 1

Remember x = 3
in while loop x in post incrementing which means x won't update after using in next statement.

So 1st time x=3which is less than 10
Then x become 3+2 equals to 5 then 5 which is x increment by 1 equals 6

2nd time x is 6 less than 10 true
Then x become 6+2 equals to 8 then 8 which is x increment by 1 equals 9

3rd time x is 9 less than 10 true
Then x become 9+2 equals 11 then 11 which is x increment by 1 equals 12

4th time x is 12 which is false but X is post incrementing inside while loop so it print 13 after incrementing x by 1.

Answer 2

Marcus Landry our x is at 12 when compiler check condition inside while which is x++<10 or 12 < 10 which is false so it won't go inside while loop.

In short : due to less than operator (<).

Answer 3

Thanks so much! I totally missed the loop it makes sense though bc the code will continue to run until after.

Answer 4

Yes right !!

Answer 5

So just to be sure the last one displayed will always be false? Iss the due to the while, ++ or the <?