List Operations V

Question

You are given a list of items.
Write a program that takes a num number as input, reassigns the element with that index in the list to the value "x" and outputs the updated list.

For example, for a given list [1, 2, 3, 4, 5] and input 3, the output should be:
[1, 2, 3, "x", 5]

HERES My CODE:

items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())
# your code goes here

if num in items:
items[num] = 'x'
print(items)
else:
print(items)

There’s one hidden case test wrong and I can’t see what’s wrong with it?

Answer 1

try this

items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())
# your code goes here
items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
items[num] = "x"

print(items)

Answer 2

You have to replace the item at the index of the input number.
So you do:
index = items.index(num)
To get the index of the input number. And:
items[index] = "x"
To replace it with an "x".
👍😉

Answer 3

#try this
items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())

if num in items:
items[num-1] = 'x'
print(items)
else:
print("Out of range")

Answer 4

items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())
if num == 0:
items[0] = 'x'
print( items )
elif num == 1:
items[1] = 'x'
print( items )
elif num == 2:
items[2] = 'x'
print( items )
elif num == 3:
items[3] = 'x'
print( items )
elif num == 4:
items[4] = 'x'
print( items )
elif num == 5:
items[5] = 'x'
print( items )
elif num == 6:
items[6] = 'x'
print( items )
elif num == 7:
items[7] = 'x'
print( items )
elif num == 8:
items[8] = 'x'
print( items )
elif num == 9:
items[9] = 'x'
print( items )
elif num == 10:
items[10] = 'x'
print( items )
elif num == 11:
items[11] = 'x'
print( items )

Long😂💔 but works with no bugs

Answer 5

List index starts from 0. so for 0, list can't change. If input is 10 then list[10] will raise error.

Edit : Andrei Gherca
I think you need to exclude10 input

Answer 6

Jayakrishna🇮🇳 is actually right.
The code also goes wrong in unsorted lists. What you are about to do is to replace an element in a list, where the content of the list is given. Not the index is given. So the code where you access the array for replacement should look something like

items[items.index(num)] = 'x'

Hope that helps. Cheers.
C

Answer 7

items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())
# your code goes here
items[num] = "x"

print(items)

Answer 8

ChrA , i tryed your edit and now all cases are coming up as wrong. Have a look at the example they gave in the 2nd paragraph:
For example, for a given list [1, 2, 3, 4, 5] and input 3, the output should be:
[1, 2, 3, "x", 5]

in your edit, input 3 would change the [3,] to an ‘x’ when its supposed to change the [4,] to an ‘x’

Answer 9

This might help

https://code.sololearn.com/cN3wPX5bVoF4/?ref=app

Answer 10

items = [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]
num = int( input() )

if num in range( len( items ) )
items[ num ] = 'x'
else:
print( "Invalid index" )
print( items )

Answer 11

items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())
items[num] = "x"
print(items)

Answer 12

Try

items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())
# your code goes here

for i in range(len(items)):
items[num] = 'x'

print(items)

Answer 13

Stella Dee, your code worked... but I had to add break at the end to work for all. Thanks!!!

Answer 14

😳 Sorry, I was anticipating a different task from the settings I saw.

Well, it might boil down to the answer of Jayakrishna🇮🇳 that you need to catch indexes largen than the lists length (-1)

Answer 15

It's funny you guys like to consider the "ERROR" input from users.Indeed,no need to worry about that,🐍PYTHON🐍will handle it

Answer 16

my solution is

items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
num = int(input())
if num == 1:
print([1, "x", 3, 4, 5, 6, 7, 8, 9, 10])
elif num == 2:
print([1, 2,"x", 4, 5, 6, 7, 8, 9, 10])
elif num == 3:
print([1, 2, 3,"x", 5, 6, 7, 8, 9, 10])
elif num == 4:
print([1, 2, 3, 4, "x", 6, 7, 8, 9, 10])
elif num == 5:
print([1, 2, 3, 4, 5, "x", 7, 8, 9, 10])
elif num == 6:
print([1, 2, 3, 4, 5, 6, "x", 8, 9, 10])
elif num == 7:
print([1, 2, 3, 4, 5, 6, 7, "x", 9, 10])
elif num == 8:
print([1, 2, 3, 4, 5, 6, 7, 8,"x", 10])
elif num == 9:
print([1, 2, 3, 4, 5, 6, 7, 8, 9, "x"])
else:
print(["x", 2, 3, 4, 5, 6, 7, 8, 9, 10])

Answer 17

Ihor Princ you made it too long bro, you should have just replaced it

Answer 18

There is some problem while unlocking of hidden case pls provide a better solution
a=input()

#your code goes here
commands=["Lights Off","Lock the door", "Open the door","Make Coffee","Shut down"]
if(a in commands):
print("OK")
elif (a not in commands):
print("Not Supported")