Ticket Office

Question

Why test case 3? I need an answer for this?
include <iostream>
using namespace std;
int main(){
int ages[5];

for (int i + 0; <5; i++){
cin>>ages[i];
}

int a= ages[0];
int b= ages[1];
int c= ages[2];
int d= ages[3];
int e= ages[4];

if ((a<b)&&(a<c)&&(a<d)&&(a<e)){
float w=a;
float p=(w/100)*50;
float y=50-p;
cout<<y<<endl;
}
if ((b<a)&&(b<c)&&(b<d)&&(b<e)){
float w=b;
float p=(w/100)*50;
float y=50-p;
cout<<y<<endl;
}
if ((c<b)&&(c<a)&&(c<d)&&(c<e)){
float w=c;
float p=(w/100)*50;
float y=50-p;
cout<<y<<endl;
}
if ((d<b)&&(d<c)&&(d<a)&&(d<e)){
float w=d;
float p=(w/100)*50;
float y=50-p;
cout<<y<<endl;
}
if ((e<b)&&(e<c)&&(e<d)&&(e<a)){
float w=e;
float p=(w/100)*50;
float y=50-p;
cout<<y<<endl;
}

return 0;
}

Answer 1

include <iostream>
using namespace std;

int main() {
int ages[5];
double out;

for (int i = 0; i < 5; ++i) {
cin>>ages[i];
}
//your code goes here
for (int a=1;a<5;++a)
{ int youngest=ages[0];
if(youngest>ages[a])
{
youngest=ages[a];
}
double disc;
disc = 50.0*youngest/
100;

out= 50-disc;
}
cout<<out;
return 0;
}

This is the code but it passes only
Test 1 ,3 and 5

Answer 2

#include <iostream>
using namespace std;

int main() {
int ages[5] ;
float min = ages[0],p,sum=0;

for (int i = 0; i < 5; ++i)
{
cin >> ages[i];
}

for (int i = 0; i < 5; ++i)
{
if (min > ages[i])
{ min = ages[i];
}
p = 50*(min/100) ;
sum = 50 - p ;
}

cout << sum ;
return 0;
}

Answer 3

you can try mine

/*Finding the lowest age as a percent discount*/

#include <iostream>

using namespace std;

int main() {
int ages[5]; // array of 5 empty int

for (int i = 0; i < 5; ++i) {
cin >> ages[i]; //store while in for loop
}

int min = ages[0]; // basis of minimum starting from first value

for(int i = 0; i < 5; ++i) {
if (min > ages[i]) {
min = ages[i];
} // replaces the min variable if min is greater than the next value
}

cout << 50 *(1 - (min * .01));
/* deduct percentage by 1 and multiply
by 50 to find the discounted price*/

return 0;
}

Answer 4

https://code.sololearn.com/c55aw3oXod29/?ref=app

Answer 5

Visit here for better & easy solution :-

https://code.sololearn.com/ca25a21A11a2

Answer 6

#include <iostream>
using namespace std;

int main() {
int ages[5];
double out;

for (int i = 0; i < 5; ++i) {
cin>>ages[i];
}
//your code goes here
for (int a=1;a<5;++a)
{ int youngest=ages[0];
if(youngest>ages[a])
{
youngest=ages[a];
}
double disc;
disc = 50.0*youngest/
100;

out= 50-disc;
}
cout<<out;
return 0;
}

Answer 7

Why don't I pass test case 4?

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
if (ages[0] < ages[1,2,3,4] ) {
cout << 50 - 50*ages[0]/100.00;
}
else if (ages[1] < ages[0,2,3,4] ){
cout << 50 - 50*ages[1]/100.00;
}
else if (ages[2] < ages[0,1,3,4] ){
cout << 50 - 50*ages[2]/100.00;
} //your code goes here
else if (ages[3] < ages[1,2,0,4] ){
cout << 50 - 50*ages[3]/100.00;
}
else if (ages[4] < ages[1,2,0,3] ){
cout << 50 - 50*ages[4]/100.00;
}
else {
cout << 50 - 50*ages[0]/100.00;
}
return 0;
}

Answer 8

Just add a new if statement with the same code, but for test 3 specifically (all ages are the same).

Hence:

if ((a == b) && (a == c) && (a == d) && (a == e)){
float w = a;
float p = (w / 100) * 50;
float y = 50 - p;
cout << y << endl;
}

Answer 9

✔️✔️✔️✔️✔️All Test cases passed OK

#include <iostream>
using namespace std;
int main() {
int ages[5];
int x;
for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
x = ages[0];
for (int j = 0; j < 5; ++j) {

if(ages[j] < x){
x = ages[j];
}
}

cout << 50-((50.0*x)/100) << endl;

return 0;
}

Answer 10

all 5 cases are ✔️

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
int youngest = ages[0];

for (int i = 1; i < 5; i++){
if(youngest > ages[i]){
youngest = ages[i];
}
}
float discount = 50 * (float)youngest / 100;
float price = 50 - discount;

cout<< price;
return 0;
}

Answer 11

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here
float m;
float p;
m = ages[0];
for (int x = 1; x < 5; ++x) {
if ( m > ages[x]) {
m = ages[x];
}
}
p = 50 - (50*m/100);
cout << p << endl;

return 0;
}

it's working

Answer 12

You can also try this
#include <iostream>
using namespace std;

int main() {
int ages[5];
double finalCost;

for (int i = 0; i < 5; i++) {
cin >> ages[i];
}
//your code goes here
double youngest_age;
youngest_age = ages[0];
for (int a =0; a < 5; a++){
if (youngest_age > ages[a]){
youngest_age = ages[a];
}

}
finalCost = 50 - (50 * youngest_age / 100);
cout << finalCost << endl;
return 0;
}

Answer 13

This was my solution:
#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here
float min = ages[0];

int arrSize = sizeof(ages)/sizeof(ages[0]);
for(int i = 0; i < 5; i++)
{
if(ages[i] < min)
{
min = ages[i];
}
}

float price = (arrSize * 10);
float discount = (price/100 * min);
float answer = price - discount;
cout << answer << endl;

return 0;
}

Answer 14

int main() {
int ages[5];
int tsml = ages[0];

for (int i = 0; i < 5; i++) {
cin >> ages[i];
}

for (int i = 0; i < 5; i++) {
if(ages[i]<tsml)
{tsml = ages[i];}
}
cout << 50-((50.0*tsml)/100) << endl;
return 0;
}

Answer 15

short and good!

data = {
"100-90": 25, "42-01": 48, "55-09": 12, "128-64": 71, "002-22": 18, "321-54": 19, "097-32": 33, "065-135": 64, "99-043": 80, "111-99": 11, "123-019": 5, "109-890": 72, "132-123": 27, "32-908": 27, "008-09": 25, "055-967": 35, "897-99": 44, "890-98": 56, "344-32": 65, "43-955": 59, "001-233": 9, "089-111": 15, "090-090": 17, "56-777": 23, "44-909": 27, "13-111": 21, "87-432": 15, "87-433": 14, "87-434": 23, "87-435": 11, "87-436": 12, "87-437": 16, "94-121": 15, "94-122": 35, "80-089": 10, "87-456": 8, "87-430": 40
}
age = int(input())
ppl_above_18 = 0
ppl_below_18 = 0
ppl_above_age = 0
ppl_below_age = 0
for person_age in data.values():
if person_age < 18:
ppl_below_18 += 1

else:
ppl_above_18 += 1

if person_age < age:
ppl_below_age += 1

else:
ppl_above_age += 1
old_amt = ppl_below_18 * 5 + ppl_above_18 * 20
new_amt = ppl_below_age * 5 + ppl_above_age * 20
extra_profit = ((new_amt - old_amt) / old_amt) * 100
print(int(extra_profit))

Answer 16

short and good!

#include <iostream>
using namespace std;
int main()
{int ages[5];
for (int i = 0; i < 5; ++i) {
cin >> ages[i];}
float m;
float p;
m = ages[0];
for (int x = 1; x < 5; ++x)
{if ( m > ages[x])
{m = ages[x];}}
p = 50 - (50*m/100);
cout << p << endl;
return 0;}

Answer 17

data = {
"100-90": 25, "42-01": 48, "55-09": 12, "128-64": 71, "002-22": 18, "321-54": 19, "097-32": 33, "065-135": 64, "99-043": 80, "111-99": 11, "123-019": 5, "109-890": 72, "132-123": 27, "32-908": 27, "008-09": 25, "055-967": 35, "897-99": 44, "890-98": 56, "344-32": 65, "43-955": 59, "001-233": 9, "089-111": 15, "090-090": 17, "56-777": 23, "44-909": 27, "13-111": 21, "87-432": 15, "87-433": 14, "87-434": 23, "87-435": 11, "87-436": 12, "87-437": 16, "94-121": 15, "94-122": 35, "80-089": 10, "87-456": 8, "87-430": 40
}
age = int(input())
#your code goes here
ppl_above_18 = 0
ppl_below_18 = 0
ppl_above_age = 0
ppl_below_age = 0

for person_age in data.values():
if person_age < 18:
ppl_below_18 += 1

else:
ppl_above_18 += 1

if person_age < age:
ppl_below_age += 1

else:
ppl_above_age += 1

old_amt = ppl_below_18 * 5 + ppl_above_18 * 20
new_amt = ppl_below_age * 5 + ppl_above_age * 20
extra_profit = ((new_amt - old_amt) / old_amt) * 100

print(int(extra_profit))

Answer 18

Post the challenge description please