Ticket office C++

Question

You are working on a ticketing system. A ticket costs $10.
The office is running a discount campaign: each group of 5 people is getting a discount, which is determined by the age of the youngest person in the group.
You need to create a program that takes the ages of all 5 people as input and outputs the total price of the tickets.

Sample Input:
55
28
15
38
63

Sample Output:
42.5
MY CODE:
#include <iostream>
using namespace std;
int main()
{
int ages[5];
for(int i=0; i<5; i++){
cin >> ages[i];
}
int temp = ages[5];
for(int i=0; i<5; i++)
{
if(temp>ages[i]){
temp = ages[i];
}
}
float d = 50*(temp/100.00);
float total = 50-d;
cout << "

Answer 1

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here
int temp = ages[0];
for(int i=0; i<5; i++)
{
if(ages[i]<temp){
temp = ages[i];
}
}
float d = 50*(temp/100.00);
float total = 50-d;
cout << total;

return 0;
}

This is working properly.

Answer 2

I use pointer. This is work.

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here
int sum = *ages;

for (int j = 0; j < 5; j++) {
if(*(ages + j) < sum){
sum = *(ages + j);
} else {
sum = sum;
}
}

double percen = (double) 50 * sum / 100;
double result = (double) 50 - percen;
cout << result;
return 0;
}

Answer 3

My solution:
#include <iostream>
using namespace std;

int main() {
int ages[5];
int a = ages[1];
for (int i = 0; i < 5; ++i) {
cin >> ages[i];

if (a > ages[i]) {
a = ages[i];
}

}
double b = a*(50/100.00);

cout << 50 - b;
return 0;
}

Answer 4

The problem is that you initialize "temp" with the value ages[ 5 ], which is undefined since it is no element of the array. I would suggest you to choose ages[ 0 ] instead, which also lets you skip the first loop cycle, i.e.

int temp = ages[ 0 ];

for ( int i = 1; ... )
...

Regarding the duplicate post:
Just delete the other, unused one, and everything is fine.

Tips for questions:

https://www.sololearn.com/Blog/38/8-simple-rules-to-get-help-from-the-community

Answer 5

This code is correct

// your code goes here
int temp = ages[0] ;
for (int i=0; i<5; i++)
{
if(temp>ages[i])
{
temp = ages[i] ;
}
}
float d = 50*(temp/100.00);
float total = 50-d;
}

Answer 6

#include<iostream>
using namespace std;
int main(){
int ages[5];
int young;

for (int i=0 ; i < 5; i++){
cin>> ages[i];
}
young = ages[0];
for ( int i=0; i < 5 ; i++){
if (young > ages[i]){
young = ages[i];
}
}

float discount = young/100.0;
int total = sizeof(ages)/sizeof(ages[0])*10;
float afterDiscount = total - (total * discount);
cout << afterDiscount;

return 0;

}

Answer 7

Don't post same question repeatedly

Answer 8

I don't understand you

Answer 9

Sorry for that.
It's my 2nd question in this app. For that I don't know proper asking process.

Answer 10

Sumit Kumar thanks

Answer 11

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here
int temp=ages[0];
for(int i=0;i<5;i++)
{
if(temp>ages[i])
temp=ages[i];
}
float price=50-((temp/100.0)*50);
cout<<price<<endl;
return 0;
}

Answer 12

#include <iostream>
using namespace std;

int main() {
int ages[5],min ;
float dis;

for (int i = 0; i < 5; i++) {
cin >> ages[i];
}
min= ages[0];
for(int i = 1;i <5; i++){
if( min >ages[i]){
min = ages[i];

}

}

dis = 50*(min/100.00);
float t= 50-dis;
cout << t<<endl;

//your code goes here

return 0;
}

Answer 13

Why you posted the same question twice

It is considered spam

Answer 14

Try this code. it's working

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
int n = sizeof(ages)/sizeof(ages[0]);
int minimum = ages[0];
for(int i=0; i<n;i++)
{
minimum = min(minimum, ages[i]);

}
double d = 50*(minimum/100.00);
double total = 50 - d;
cout<<total;
return 0;
}

If you have any doubts or issues then you can ask me.