Hera a problem. If we put more then 10 digits then it print 7 why? Otherwise it work well for print last digit. Anyone solve it.

Question

#include <iostream>
using namespace std;

int main() {
int a;
cout << "Provide a number: \n";
cin >> a;
cout << "Last digit of provided number is " << a%10;
return 0;
}

Answer 1

use long int or string

long int x = 17L;
printf("%ld\n", x);

Answer 2

Thanks i can!

Answer 3

I want to print last digit from many digits which user input. But it work well for less than 10 digits. But it doesn't work More then 10 digits. Then how i can do.

Answer 4

I hope this link helps you

https://www.sololearn.com/Discuss/1294618/remainder

Answer 5

What was the number you used? the one with more than 10 digits?

It might be an overflow issue.

Answer 6

Apparently cin recognizes the overflow. Instead of wrapping around to negative numbers it assigns the maximum int value to a, which happens to end in 7. Here is a modification that tells the user how large the number can be:

#include <iostream>
#include <limits>
using namespace std;

int main() {
int a;
cout << "Provide a number up to " << INT32_MAX << ": \n";
cin >> a;
cout << a << "\n" << "Last digit of provided number is " << a%10;
return 0;
}

Answer 7

Thanks

Answer 8

Yeah i clearly understand.