How to get first 4 digits of integers reversed, instead of whole ( if i want o/p to be 4321)

Question

class Main {
public static void main(String[] args) {
int num = 1234567, reversed = 0;
for(;num != 0; num /= 10) {
int digit = num % 10;
reversed = reversed * 10 + digit; } System.out.println("Reversed Number: " + reversed);
}
}

O/p- Reversed Number:7654321

Answer 1

Take another variable count for counting number digits, and now here equal to 7
You need only 4 digits so 7-4=3 and divide reversed number ny 10^3 which gives you dividend 7654. hope it helps....

edit:
from 1234567,
reverse = 7654321
for 7654 => 7654321/1000 (last 4 digits)

for 4321 => 7654321%10000 (first 4 digits)
or
else do => 1234567/1000 => 1234, reverse it..