Explain this code. How yes come???

Question

x=2
y=1
if 1+1!=y or x==x and 7==8:
print("yes")
elif x>=y:
print("no")

output :-yes

Answer 1

7==8? False.... (A)
x==x? True.... (B)
B && A... False...(C)
1+1!=y?... True...( D)
D || C... True..
Thus "yes"

Answer 2

@debug the OR operator has a lower precedence than the AND operator, so && first before ||.

Answer 3

x==x(true) && 7==8(false) --- 0(False)
1+1!=y(true) or 0(false) --- True
output "yes"
the other statements inside the if... else block is left over even if they evaluates to true.

Answer 4

1+1 not equal to 1 - true
-----or-----
x is equal to x - true
___________________________________________________________________
True.
-----and-----
7 is equal to 8 - false
__________________________________________________________________
False.
Hence the answer should be false.
Try out in PC.