what is output

Question

static int calc(int from, int to, int step=1) {
int res=0;
for(int i=from;i<to;i+=step) {
res += i;
}
return res;
}
static void Main(string[] args)
{
int res =

(

2,

99,

5);
Console.WriteLine(res);
}

Answer 1

there is an error

Answer 2

static int calc(int from, int to, int step=1) {
int res=0;
for(int i=from;i<to;i+=step) {
res += i;
}
return res;
}
static void Main(string[] args)
{
int res =

calc

(

step:

2,

to:

99,

from:

5);
Console.WriteLine(res);
}

Answer 3

990 after correction

Answer 4

Call the method using named arguments with the values 5 for "from", 99 for "to" and 2 for "step":

static int calc(int from, int to, int step=1) {
int res=0;
for(int i=from;i<to;i+=step) {
res += i;
}
return res;
}
static void Main(string[] args)
{
int res =

calc

(

step:

2,

to:

99,

from:

5);
Console.WriteLine(res);
}

Answer 5

static int calc(int from, int to, int step=1) {

int res=0;

for(int i=from;i<to;i+=step) {

res += i;

}

return res;

}

static void Main(string[] args)

{

int res = calc ( step: 2, to: 99, from: 5);

Console.WriteLine(res);

}

Answer 6

Named Arguments
Call the method using named arguments with the values 5 for "from", 99 for "to" and 2 for "step":
static int calc(int from, int to, int step=1) {

int res=0;

for(int i=from;i<to;i+=step) {

res += i;

}

return res;

}

static void Main(string[] args)

{

int res =
calc
(
step:
2,
to:
99,
from:
5);

Console.WriteLine(res);

}