whats the wrong in this code (solution for 2nd degree function)

Question

#include <iostream>
#include <cmath>
using namespace std;
int main(){
cout << "please enter a, b , c \n";
double a, b, c, d, x1, x2;
cin >> a >> b >> c;
if (a = 0)
x1 = x2 = -c / b;
else
d = pow(b, 2) - 4 * a*c;
if (d > 0)
cout << "there is no real root \n";
else
{
x1 = (-b + sqrt(d)) / 2 * a;
x2 = (-b - sqrt(d)) / 2 * a;
cout << "the root is real \n ";
cout << "x1=" << x1 << "x2=" << x2;
}

return 0;

Answer 1

Hmm, let see... At first you have to use == in if() to check equality a to 0, not = . Then there is no any exception for case when user entering both a and b as 0, so in this case you have abnormal termination caused by division by zero in x1 = x2 = -c/b. Also you forget } after return 0. Hope this will help! :)