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double arr[]={5,2,7,8,11,9};
int n = sizeof(arr) / sizeof(arr[0]);
double sum = 0;
for(int i=0;i<n;i++)
{
sum+= arr[i];
}
double avg = sum / n;
cout<< "avarage ="<< avg<< endl;
return 0;
)
/*what does int n= sizeof(arr[]) /sizeof(arr[0]);
do, can someone explain that line for me*/
0 Voto
3 Respostas#include <iostream>
using namespace std;
int calc(int &a,int &b,int c=6)
{
a+=b;
b-=c;
c=a+b;
}
int main()
{
int calc(int,int,int);
int x=2,y=3,z=4; cout<<x<<endl<<y<<endl<<z<<endl;
calc(x,y,z); cout<<x<<endl<<y<<endl<<z<<endl;
calc(5,6,z); cout<<x<<endl<<y<<endl<<z<<endl;
return 0;
}
1 Voto
5 Respostas#include <iostream>
#include <bitset>
int main()
{
int myDecimalNumber;
std::cin >> myDecimalNumber;
std::string binary = std::bitset<8>(myDecimalNumber).to_string(); //to binary
std::cout<<binary<<"\n";
unsigned long decimal = std::bitset<8>(binary).to_long();
std::cout<<decimal<<"\n";
return 0;
}
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