Pointers C

Question

void test(int k);

int main() {
int i = 0;

printf("The address of i is %x\n", &i);
test(i);
printf("The address of i is %x\n", &i);
test(i);

return 0;
}

void test(int k) {
printf("The address of k is %x\n", &k);
}

Why does it give a different adress when "i" is accessed through the function test and ehen through printf?

Answer 1

Because i and k are different variables, therefore they allocate in memory on different places hence have different addresses