why it is not working for Letter Counter in intermediate python

Question

text = input()
dict = {}
for x in text:
dict[x]+=1
print(dict)

I have done this without checking dict using if

Answer 1

The code outputs error if x is not a key of dict.

Answer 2

JUMP_LINK__&&__Python__&&__JUMP_LINK Building up based on CarrieForle's answer, here are three possibilities:

text = input()
dict = {}

#1
for x in text:
if x in dict: dict[x] += 1
else: dict[x] = 1
print(dict)

#2
for x in text:
dict = dict.get(x, 0) + 1
print(dict)

Or just

#3
print({x: text.count(x) for x in text})

# I hope that this answer helps you with your question. If I have made a mistake in any part of my answer, just let me know. Happy coding!

Answer 3

JUMP_LINK__&&__Python__&&__JUMP_LINK

Your code will give error because there is no key in dictionary so 1st you need to check if key exist in dictionary then increment counter otherwise assign 1 to dictionary.

text = input()
dict = {}
for x in text:
if x in dict:
dict[x]+=1
else:
dict[x] = 1
print(dict)

https://code.sololearn.com/cebXGf11Gq58/?ref=app