What is the output of this code? And How?

Question

hash = Hash.new()
hash[9] = "a"
hash[8] = "b"
hash[7] = "c"
hash[6] = "d"
print hash.count ()
hash.delete[9]
print hash.count()

Answer 1

in Ruby everything is an object so first
hash = Hash.new()//this is used to create hash
hash[9] = "a"//first value in hash
hash[8] = "b"//2nd value in hash
hash[7] = "c"//3rd value in hash
hash[6] = "d"//4th value in hash
print hash.count ()//it will count the value in hash which is 4
hash.delete[9]//it will delete the value" b"
print hash.count()//now count become 3
so output is 43

Answer 2

Remove space in line 6:
print hash.count()
Change braces in line 10:
hash.delete(9)
Then you'll get the output you expected ;)