I gett an unwanted "none" as an output while using fuction in for lopp

Question

My code:

people = ["oscar", "carl", "jenny"]

def add_and(name):
print(name + " and")

for x in people:
print(add_and(x))

output:
> oscar and
> none
> carl and
> none
> jenny and
> none

why does this happen, where does "none" come from?

Answer 1

print(function) prints the return value of the function. The return value of the print() function is None. Thus, print(print(string)) prints string and None.

Answer 2

Change print to return in your function and all will be 👌.

Answer 3

Yes, it's always from the inside to the outside

Answer 4

okej so i have solved this but will leave the post up if anyone is curious.

The error occurs because print() is used twice. If we look att the first loop then x will be "oscar". What im telling the program is:

print(add_and(x)) --> print(print(oscar + " and")).

It's not necessary to use print() twice. But I dont really undersand why " oscar and" and "none" is the output.

Answer 5

so in the text: print(print(string))
the part: print(string) is run first?