Why given below code's output is false?

Question

var a=[1,2,3,'hi'];
var b=[1,2,3,'hi'];
console.log(a == b);

Answer 1

ILLUMINATIE so works it in javascript. Javascript offers no possibility to compare of objects.

Answer 2

That are different objects. The objects are equal as follows.
let objectA= {value: 50};
let objectB= objectA;
let objectC= {value: 50};

console.log(objectA==objectB; // → true
console.log(objectA== objectC);
// → false“

Answer 3

A and b are not the same, because if you for example change a to [1,2,3,’hello’] then b would stay the same....

Answer 4

👍👍thank you for explaining this,stay happy with play coding friends,once again thank you for all!😃😃

Answer 5

ILLUMINATIE you are welcome! It was a honour to answer your question! happy coding
(btw.: If you question is solved you could edit it and add solved tag...)

Answer 6

var a=[1,2,3,'hi'];
var b=[1,2,3,'hi'] ;

console.log(a == b); //false

Because it compares refference for Arrays by == opearator.
Look this:

var a = [1,2,3,'hi'];
var b=a,
console.log(a == b) ; //true

By b=a, now both points same address.

Answer 7

js does not directly compare directly to any object, it will ask for a reference !. here it is right, friends?

Answer 8

Yes, ILLUMINATIE . Array is an object and here javascript up to now compares they references only and not properties of them.

Answer 9

No,it is confused me!