why does the output is 7 instead of 16 ?????

Question

#include <stdio.h>
#define sqr(x) x*x
int main()
{
printf("%d", sqr(3+1));
return 0;
}

Answer 1

#define only replaces the variable name with the value. So,

sqr(3+1) = 3+1*3+1 = 3+3+1 = 7

To get 16 as output, you need to use parentheses. Like this:

#define sqr(x) (x)*(x)

Answer 2

To get output 16 you may use

#define sqr(x) (x)*(x)

Then output will be
(3+1)*(3+1)
(4)*(4)
16

Answer 3

Rajesh Dutta oo, sorry. My bad 😅
I wrote 9 instead of 7 by mistake 😁

Answer 4

Martin Taylor Genuine Stalwart Sayed🇧🇩🇧🇩 This was in solo learn challenge, solo learn challenged me and the question was as it is like this, the correct answer says 7

Answer 5

Genuine Stalwart thanks i finally understood that problem 👏👏

Answer 6

Martin Taylor sololearn actually challenged me and this was the question as it is written so, i answered 16 but it showed correct answer is 7👍