why the output is 1

Question

#include <iostream>
#include <string>
using namespace std;

int myClass() {
int x = 5;
return x;
};

int main() {
cout << myClass ;

return 0;
}

//why the output is 1?

Answer 1

It's because you use the myClass function without parentheses. Use myClass() instead. Also it's seems like a bad idea to call a function a class...

Answer 2

i believe it is because when you cout << function; (without the () )
you ask if it exists. so the return is 1 because true

not completely certain though

Answer 3

Thx~

Answer 4

but i havnt define the variable myClass 🤔how can it output 1,where does the value 1 come from?

Answer 5

name of the function is a pointer and pointer is convertible to bool.
so cout << myClass is checking if(myClass) since myClass has some address it evaluates to true. true is further convertible to integer, hence you are getting 1 as output.

try this
int *ptr = nullptr;

cout << ptr; // output 0, since ptr is nullptr. All non-zero values are true in C/C++ other languages.