[ C ]Having a problem in building program.

Question

My code is as follow:
#include<stdio.h>
int main(void)
{
int a,b,c,d,e;
float f;
printf("Enter a:\n");
scanf("%d",&a);
printf("Enter b:\n");
scanf("%d",&b);
c=a+b;
d=a-b;
e=a*b;
f=a/b;
printf("c=%d\n,d=%d\n,e=%d\n,f=%d\n",c,d,e,f);
return 0;
}
There is a trouble in division.I can't get the correct answer.I have tried a lot of way, including forced-type-transfer.However, I still cannot get a correct answer.Can anyone help me?

Answer 1

Use float or double data types instead of int.
You'll need to use %f or %lf format specifiers

●Dividing int by int will result in int only , fractional part is ommited.

●Even if you typecast result to float *after* division , you'll get float number but it'll have 0's after decimal point
ex. (float)(3/2) will result in 1.0 not 1.5

●You can follow this way
(float)3/(float)2

●Even if you have a variable of type float using it against %d format specifier will cause implicit typecasting to int

https://codeforwin.org/2015/05/list-of-all-format-specifiers-in-c-programming.html

Answer 2

Elder notice these line
scanf("%d",&a);
scanf("%d",&b);

You are taking input as integer(using %d) so even if you give float numbers they will be converted to integer.
You can replace it with scanf("%f",&a);
scanf("%f",&b);

Answer 3

Elder can't say anything without watching your code , what you have changed.

Post it in playground and link it to your question

https://www.sololearn.com/post/75089/?ref=app

Answer 4

update:I've tried such way to solve my problem,but still the app show some unexpected behavior.I wonder whether is the complier`s problem.

Answer 5

have try,but the answer is still wrong.it seems like some sort of overflow.in fact,all calculation show error.